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Old 04-09-2007, 07:27 PM   #1
mot
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Default determining ABV

What is the math to determine ABV again. Something like OG - FG divided by 150 times something.

I cant find the math problem anywhere, you guys remember it?


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Old 04-09-2007, 07:30 PM   #2
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Oh yeah and a bottling question, Mine is in the secondary at the moment, is it easier to bottle right from there or should I transfer it into my bottling bucket, with the spigot?


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Old 04-09-2007, 07:36 PM   #3
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Quote:
Originally Posted by mot
What is the math to determine ABV again. Something like OG - FG divided by 150 times something.

I cant find the math problem anywhere, you guys remember it?
Not sure what the math is but John Palmer has a table on his website howtobrew.com.

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Originally Posted by mot
Oh yeah and a bottling question, Mine is in the secondary at the moment, is it easier to bottle right from there or should I transfer it into my bottling bucket, with the spigot?
I would go with the bottling bucket myself.
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Old 04-09-2007, 08:06 PM   #4
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couldnt find the chart, Ill have to do some searching for the math problem
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Old 04-09-2007, 08:11 PM   #5
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I think the formula is:

ABV = (OG - FG)*131

so a 1.050 beer that finished at 1.007 would have about 5.6% ABV

(1.050 - 1.007) * 131 = .043 * 131 = 5.633

Promash says it shoulf be 5.66%. Close enough for me.

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Old 04-09-2007, 08:13 PM   #6
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I always thought that you subtract the FG from the OG and multiply the difference by 131.
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Old 04-09-2007, 08:15 PM   #7
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thanks guys, I thought there was a few more steps in it but I could very well be wrong
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Old 04-09-2007, 08:17 PM   #8
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Og - Fg * 105 = Abw

Abw * 1.25 = Abv
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Old 04-09-2007, 08:18 PM   #9
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i use... ABV = (OG - FG)*131
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Old 04-09-2007, 08:19 PM   #10
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Here is the link to Palmer's table.
http://www.howtobrew.com/section1/chapter9-4.html


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