Alright, we just had our summer wit go into the fridge, and pulled a sample...and there's something off about it. We figured it's time to address water quality, as we haven't been looking at pH at all. After much reading and note taking, I have this example set up, but it seems to be excessively high. Can anyone point me in the right direction?
Latic acid at 88% in solution drops pH by .1 at .09036g of lactic acid/lb of grain.
Water pH is 7.0, we want pH of 5.6, so a drop in pH of 1.4 is needed.
.09036g/.1pH drop = Xg/1.4 pH drop needed
x=1.31g needed for every lb of grain to get it to drop to 5.6.
There are 1214mg/mL in lactic acid. This is equal to 1.214g/mL, or in 1mL/1.214g.
If we intend on 5 lbs of grain, then 5 x 1.31g x 1mL/1.214mL=5.39mL
needed to add.
That seems like quite a bit when most people I saw were adding only 1-3mL. Anyone have any input?