just a quick question i could not find an answer to..
Lets say for example i have a 10lb grain bill for a 5.5 gal recipe.
so using the standard 1.25qt per lb for mash and .5 gal per lb for sparge. That would equal to 3.25gallons mash + 5 gallons sparge = 8.25 gallons in the brewpot (for BIAB)
now because it's 10gal we'll account for around .1 gal per lb of grain for absorbtion.
so original water 8.25 gal - 1 gal for grain absorbtion = 7.25 gallons.
now we'll figure my boil off volume as 1 gal an hour.
so after grain absorbtion i'll have 7.25 gallons of water, minus 1 gal of water for boil off, that leaves me 6.25 gallons of wort for the fermenter... which i wanted 5.5 gallons into the fermenter. so would i boil the original wort down to lets say a tad over 6.5 gallons to account for the 1 gallon of boil off im' about to have, and then start the timer for the 60 mins?
this is the only thing i am having an issue with on finding an answer,