

02222010, 09:23 PM

#1

Feb 2010
Louisiana
Posts: 862
Liked 46 Times on 30 Posts

I brewed a nice IPA yesterday (with a brewhouse efficiency of 68%, I estimated the OG to be 1.068):
Pale Malt (2Row): 13.5#
Carapils: 1#
Crystal 40L: 1#
Batch size: 5.5 gallons.
I mashed with 4.84 gallons (heated to 170F) at 153F for 60 minutes. After the mash, my temp. was 152F. 1 degree loss is not too shabby.
I then mashedout with 2.14 gallons (heated to 210F) to make up for grain absorption which increased the temp to 165F. Mixed for a minute or two, let settle for 10 minutes, vorlaufed, and collected 5.1 gallons at 1.071 SG.
I sparged with 4.8 gallons (heated to 181F) which increased the temp to 168F. Mixed for a minute or two, let settle for 10 minutes, vorlaufed, and collected 4.45 gallons at 1.039 SG.
Total to kettle was 9.55 gallons at 1.051 SG (after mixing the collections).
After boiling, I collected 5.75 gallons to fermenter at 1.060 SG. There was about 0.9 gallons left that I could have collected if I had the room.
I calculated my efficiency to be 60% (based on the 5.5 gallon batch size). If I base it on my actual collected volume (5.75 gallons), it's 63%. And if I add in the extra 0.9 gallons in the kettle that I could have collected, it's 70%. But maybe I shouldn't care about the extra left in the kettle.
So my questions are:
(1) Are my calculations correct?
(2) What could I do to increase my efficiency?



02222010, 09:29 PM

#2

Dec 2008
Reading PA
Posts: 437
Liked 2 Times on 2 Posts

your eff is based on preboil volume and how did you boil off nearly 4g. Did you do an iodine test to see if you converted all starch and what is your preboil gravity. Your eff is based on the amount of grain, the yield for each grain, your preboil volume and preboil gravity



02222010, 09:36 PM

#3

Vendor and Brewer
Aug 2006
Whitehouse Station, NJ
Posts: 23,333
Liked 1765 Times on 1122 Posts

Wait, did you really boil down from 9.55 gallons to 6.75? How long did that take?
I just think you sparged a little too much and left a gallon of wort in the kettle which kills brewhouse efficiency.
Batch size 5.5, figure about 1.5 gallons of boil off in an hour. Total preboil should be 7 gallons.
15.5 pounds of malt x 1.25 qts/lb is 19.375qt or just call it 5 gallons. The grain will hold on to about 1.9 gallons... call it 2. Your first runnings would be 3 gallons. You would then need to sparge with 4 gallons to get your 7 gallons of preboil volume.
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02222010, 09:41 PM

#4

Aug 2009
Twin Cities, MN
Posts: 2,509
Liked 35 Times on 35 Posts

Quote:
Originally Posted by jgourd
I brewed a nice IPA yesterday (with a brewhouse efficiency of 68%, I estimated the OG to be 1.068):
Pale Malt (2Row): 13.5#
Carapils: 1#
Crystal 40L: 1#
Batch size: 5.5 gallons.
I mashed with 4.84 gallons (heated to 170F) at 153F for 60 minutes. After the mash, my temp. was 152F. 1 degree loss is not too shabby.
I then mashedout with 2.14 gallons (heated to 210F) to make up for grain absorption which increased the temp to 165F. Mixed for a minute or two, let settle for 10 minutes, vorlaufed, and collected 5.1 gallons at 1.071 SG.
I sparged with 4.8 gallons (heated to 181F) which increased the temp to 168F. Mixed for a minute or two, let settle for 10 minutes, vorlaufed, and collected 4.45 gallons at 1.039 SG.
Total to kettle was 9.55 gallons at 1.051 SG (after mixing the collections).
After boiling, I collected 5.75 gallons to fermenter at 1.060 SG. There was about 0.9 gallons left that I could have collected if I had the room.
I calculated my efficiency to be 60% (based on the 5.5 gallon batch size). If I base it on my actual collected volume (5.75 gallons), it's 63%. And if I add in the extra 0.9 gallons in the kettle that I could have collected, it's 70%. But maybe I shouldn't care about the extra left in the kettle.
So my questions are:
(1) Are my calculations correct?
(2) What could I do to increase my efficiency?

You got 70% efficiency. That liquid left in the kettle counts! Think about it...if you had boiled longer, you would have been left with less in the kettle after transferring to the fermenter.....less water=more concentrated=higher OG. So, if you are looking at "post boil efficiency", you need to account for ALL the liquid.
Which is why many go by "preboil" efficiency more...you are usually measuring how much wort you have preboil, so the calculations are easier.



02222010, 10:54 PM

#5

Feb 2010
Louisiana
Posts: 862
Liked 46 Times on 30 Posts

For those who are wondering how I boiled off so much, I didn't. It was a 90 minute boil, and I actually only lost 1.7 gallons due to evaporation (13% rate). Between the bottom of the keggle and the counterflow chiller, I have 1.1 gallons lost. So 0.9 extra wort + 1.1 lost + 5.75 collected + 1.7 evaporated = 9.42 which was basically my preboil volume. SG of preboil volume was 1.051. How would I perform the calculation to get preboil efficiency?
And another question. What's the calculation then for determining how much grain I'd need to hit a preboil efficiency with a brewhouse efficiency of 68%? And also supposing my batch size were 5.5 gallons?
Thanks.



02232010, 12:24 AM

#6

Dec 2008
Reading PA
Posts: 437
Liked 2 Times on 2 Posts

This should get you started but there are charts out there for the yield in PPG point per pound grain per gallon
2row is about 35 PPG x 13.5 = 472.5
preboil volume 9.42
preboil gravity 1.050 or 50 points
50 points X 9.42 = 471
471/472.5 = 99% eff
I also did your preboil gravity and what it should be post boil according to pre and post volume and I got 1.081 OG post boil. So you might wanna check your numbers



02232010, 12:45 AM

#7

Dec 2008
Reading PA
Posts: 437
Liked 2 Times on 2 Posts

Quote:
Originally Posted by jgourd
And another question. What's the calculation then for determining how much grain I'd need to hit a preboil efficiency with a brewhouse efficiency of 68%? And also supposing my batch size were 5.5 gallons?
Thanks.

what is the OG post boil? If its 1.040 then 40 x 5.5 = 220 points you need. 2row PPG is 35 x .68(eff) = 23.8. 220/23.8 = 9.24 lbs of 2row for 68% eff.



02232010, 01:05 AM

#8

Feb 2010
Louisiana
Posts: 862
Liked 46 Times on 30 Posts

Quote:
Originally Posted by kryolla
This should get you started but there are charts out there for the yield in PPG point per pound grain per gallon
2row is about 35 PPG x 13.5 = 472.5
preboil volume 9.42
preboil gravity 1.050 or 50 points
50 points X 9.42 = 471
471/472.5 = 99% eff
I also did your preboil gravity and what it should be post boil according to pre and post volume and I got 1.081 OG post boil. So your numbers are wrong

OK. Let me see if I have this right. First the grain points I used:
2row PPG is 36 and I have 13.5#
Carapils is 33 and I have 1#
Crystal 40 is 34 and I have 1#
So 13.5 * 36 + 33 + 34 = 553
And now here's how I calculate my preboil efficiency (with preboil SG=1.051 and preboil volume=9.42):
51 * 9.42 / 553 = 87%
And now efficiency based on what I collected to the fermenter (plus extra 0.9 left in kettle above normal trub loss):
60 * 6.65 / 553 = 72%
And now efficiency just based on what my batch volume was set to (5.5):
60 * 5.5 / 553 = 60%
So as I figure it, brewhouse efficiency is just a way to work backwards. To help you figure out how much grain you need to hit a certain SG considering your brewhouse efficiency. Or the other way around: given some amount of grain, the potential you will get out of it per your equipment based on the brewhouse efficiency. Am I getting this right?



02232010, 01:07 AM

#9

Jan 2010
Medford, MA
Posts: 4,125
Liked 125 Times on 121 Posts

were all those SGs not temp corrected?



02232010, 01:12 AM

#10

Feb 2010
Louisiana
Posts: 862
Liked 46 Times on 30 Posts

Quote:
Originally Posted by dcp27
were all those SGs not temp corrected?

They were corrected. Preboil SG was 1.051. Postboil SG was 1.060.





