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Old 01-04-2010, 05:05 PM   #1
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Default AA% conversion

Hey guys
I'm trying to convert a simple hop schedule to hit the desired IBU mark. The hops my LHBS carries are 4.5% and the recipe I am going from used 5.0%.

The recipe adds 1.0 oz Kent Goldings (5.0%) at 60 minutes, for 17.2 IBU. How many ounces of Goldings do I need to add at 60 minutes to hit 17.2 IBU?

Recipe: 1.0oz (5.0%) 60 min = 17.2 IBU
Me: ???oz (4.5%) 60 min = 17.2 IBU


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Old 01-04-2010, 05:11 PM   #2
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Here is the equation.

IBU = [W(oz)*AA%*U*7489]/V(gal)

the answer would be 1.02

IBU = [1.02*0.045*0.25*7489]/5

You can see by this that it doesn't matter much as I have found in brewing, ballpark is close.


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Old 01-04-2010, 05:15 PM   #3
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Quote:
Originally Posted by humann_brewing View Post
Here is the equation.

IBU = [W(oz)*AA%*U*7489]/V(gal)

the answer would be 1.02

IBU = [1.02*0.045*0.25*7489]/5

You can see by this that it doesn't matter much as I have found in brewing, ballpark is close.
It's monday morning and maybe the answer is obvious, but what does U represent?
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Old 01-04-2010, 05:20 PM   #4
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Quote:
Originally Posted by A4J View Post
It's monday morning and maybe the answer is obvious, but what does U represent?
U is the time, .25 is for 60 minutes. Here is the article.

http://www.byo.com/stories/recipes/a...lor-techniques
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Old 01-04-2010, 05:27 PM   #5
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Originally Posted by humann_brewing View Post
U is the time, .25 is for 60 minutes. Here is the article.

http://www.byo.com/stories/recipes/a...lor-techniques
utilization [time]. That's what I figured.

grassy-ass.
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Old 01-04-2010, 05:36 PM   #6
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Divide 5 by 4.5 = 1.1 oz.
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Old 01-04-2010, 06:03 PM   #7
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Thanks guys!



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