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Old 09-30-2006, 11:09 PM   #1
homebrewer_99
 
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Some of you may remember I recommend blending or mixing 2 (relatively) bad batches to make 1 good one before thinking about toss both away? Well, it came to that for me today.

In my storage room I "found" a "lost" 6er of batch # 5014, a Hefe Weizen, that I brewed on 4 Sep 05 and bottled on 8 Oct 05. Checking my notes, it was on the sweet side because I used 7 lbs of malt and only 1 oz of bittering hops.

Recently, I "inadvertently" miscalculated the bittering hops for #6017, my Hoppy Beerthday Weizen, making it more bitter than I expected (silly mistake, really), still very much drinkable, just about on the 55-60% of bitter where I prefer the 51% sweet to 49% bitter flavor.

Well, taking my own advice, I blended 4 - 0,5 liter bottles in a jug (2 from each batch) and now have a slowly dwindling jug of some good tasting Weizen.

Incidently, I only have a few bottles left so I will fancifully rename these last remaining bottles either "In with the Old and In with the New" or '05 Plus 06 Equal 11 because they were bottled 11 months from each other...OK, while that's all true, I'm not going to rename squat and just keep drinking...

Just wanted to let everyone know that I talk the brew talk and I walk the brew walk... ...blending DOES work (but I knew that).
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Old 10-01-2006, 12:16 AM   #2
david_42
 
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I'm finding the Bent Rod Rye mixed with a Red or Brown can give them a whole new range.

Homework: If you have four taps on your kegger, how many different ales can you blend assuming a half pint glass, two or more beers per sample, no less than 1 oz. of any given beer and restricting yourself to whole ounces?

Bonus points if you make it half way through the test without passing out!
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Old 10-01-2006, 01:26 AM   #3
Catfish
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I don't practice what I preach because I'm not the kind of person I'm preaching to.
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Old 10-01-2006, 03:07 AM   #4
homebrewer_99
 
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Quote:
Originally Posted by Catfish
I don't practice what I preach because I'm not the kind of person I'm preaching to.
...in your case I can fully understand...
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Old 10-01-2006, 03:08 AM   #5
homebrewer_99
 
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Quote:
Originally Posted by david_42
I'm finding the Bent Rod Rye mixed with a Red or Brown can give them a whole new range.

Homework: If you have four taps on your kegger, how many different ales can you blend assuming a half pint glass, two or more beers per sample, no less than 1 oz. of any given beer and restricting yourself to whole ounces?

Bonus points if you make it half way through the test without passing out!
Owww, I know, I know, pick me, oww, oww....the answer's 1!
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Old 10-01-2006, 03:10 PM   #6
runhard
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"Homework: If you have four taps on your kegger, how many different ales can you blend assuming a half pint glass, two or more beers per sample, no less than 1 oz. of any given beer and restricting yourself to whole ounces?

Bonus points if you make it half way through the test without passing out"

It has been over 25 years since I took calculus but combinations, permutations, and factorials will get me there, I hope. If I don't respond within 5 minutes........I passed out.

 
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Old 10-02-2006, 03:39 AM   #7
3rd and Long
 
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African or European?

But really.. do you mean how many different blends? or how many ales? and are we to assume that there isn't more been in the fridge that you don't have a picnic tap on?

Making the assumption that each tap has an ale (no lagers), then 4, one for each tap.
Unless you mean how many different blends, hmm.. then
2 beers: 42
3 beers: 84
4 beers: 35
->161 total permutations

I threw it into excel and figured it out.. so I have only little conifidence. I'd feel better if I had a formula.

 
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Old 10-02-2006, 05:01 AM   #8
Spyk'd
 
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It's a trick question, there is only one ale...



The answer is "1".




 
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Old 10-02-2006, 05:18 AM   #9
Walker
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Quote:
Originally Posted by 3rd and Long
2 beers: 42
3 beers: 84
4 beers: 35
->161 total permutations
[geek]I'm tryng to recall my prob and stats classes from college. I believe we want combinations and not permutations here. A Permutation would allow for multiple blends to be mixed that have the exact same contents, but the mixing was done in a different order. In other words, 4 ouces of IPA + 4 ounces of porter would be a different permutation than 4 ounces of porter + 4 ounces of IPA would be a different permutation than 2 oz porter + 2 oz IPA + 2 oz porter + 2 oz IPA, etc, etc.

Anyway, what you came up with were combinations, which is what we want. I just don't know if the results you have are right. I forget how to do the math these days.

Hmmm... Maybe we should get clarification from the teacher on our homework. david_42 are we counting combinations or permutations?[/geek]
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Old 10-02-2006, 07:31 AM   #10
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We're waiting...?

 
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