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Old 09-10-2006, 12:49 AM   #1
Cregar
 
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Hey all, :-)

Just picked up the rest of my equipment and going to start my first batch of mead but I have a quick question...

I am going to start with a small batch (1 gallon). So the recipe I am using calls for 3 lbs (48 ounces) of honey. Since I am doing a 1 gallon (128 ounces), does that mean I need to use only 80 ounces of water? Does the honey count as part of the liquid?

Thanks for the advice.

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Old 09-10-2006, 01:41 PM   #2
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Correct. Although technically, is part of the volume not the water.
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Old 09-10-2006, 01:44 PM   #3
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Wait a second, though; 48 ounces of honey is a weight measurement, not volume (ounces vs. fluid ounces). Not the same thing. So, you may still want to have a total volume of 1 gallon inclusive of the honey, but it's not as simple as 128oz - 48oz.
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Old 09-10-2006, 06:17 PM   #4
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ok, then should I pour the honey into something to measure the "fluid" ounces then base my water amount on that measurement?

 
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Old 09-10-2006, 09:09 PM   #5
sconnie
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all you need to do is put the honey (or honey disolved in a little water) into the primary, then fill it with water up to 1 gallon, leaving a little room for fermentation. No real need to measure out the honey in terms of liquid oz.
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Old 09-10-2006, 09:11 PM   #6
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Ok.. cool... thanks for the advice

 
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