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Old 04-28-2009, 08:26 PM   #1
hayabusa
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Jan 2009
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Google isn't providing any good solid answers on this; what is the rate of thermal shrinkage you are all experiencing when measuring your hot wort final volume vs. your cooled worts final volume?
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Old 04-28-2009, 08:27 PM   #2
GilaMinumBeer
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4% average nominal.

 
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Old 04-28-2009, 08:45 PM   #3
JumboBlimpJumbo
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Apr 2008
Norman, Oklahoma
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+1 4% average nominal.

For pure water at 100 degrees C (boiling) and standard atmospheric pressure the specific volume is .001044 m^3/kg, and .001003 at 25 C (about 77 f) which would be 3.93% ((.001044-.001003)/.001044) without taking into consideration all the dissolved sugars (which I don't think contribute too much to it.)

Got my info from Chemical, Biochemical, and Engineering Thermodynamics 4E, Stanley I. Sander

haha I knew I'd get some kind of use out of my chemical engineering books


 
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