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07-20-2006, 03:21 AM   #1
Beer Snob

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Dec 2005
Farmington
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Trying to find the answer to something. In my AG I'm using two pots. I get say 1.050 in one and lets say 1.030 in the other. I want to find efficiency but I first need to get these two numbers represented as one number. How do I do that?
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07-20-2006, 03:37 AM   #2
RichBrewer

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Feb 2006
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If you have equal volume in the pots, couldn't you add them together then divide by 2?
Maybe that's too simple.
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Rich

07-20-2006, 03:59 AM   #3
Boston

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Jan 2006
Cary, NC
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Quote:
 Originally Posted by RichBrewer If you have equal volume in the pots, couldn't you add them together then divide by 2? Maybe that's too simple.
Rich is correct.....even if the volumes were not equal you just have to "solve for x".......basically the algebra we all studied in 9th grade and swore we would never have to use in real life.
JR

07-20-2006, 06:59 AM   #4

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Dec 2005
Sammamish, WA
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In a nutshell formula woud be ((SG1 * V1) + (SG2 * V2)) / (V1 + V2). V1 and V2 are the volumes of your 2 pots in gallons.
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