I have a 15 gallon tri clad pot - the very common type. It has a false bottom at about the two gallon mark. It is direct fire (on a single tier stand with automation). I want to brew 11 gallons of imperial stout at an og of 1.090. I plan on an efficiency of 65% (I usually get 70 - 75 but I like to play it safe).
The recipe calls for a combined total of 41 lbs of grain. According to Bobby M's table - I max out at 37ish with a 15 gallon mash tun. I would be nervous even getting even close to that amount of grains in a 15 gallon pot.
What is the best way to deal with this? I'm hoping someone has a trick to do this without having to essentially mash twice. The only thing I have come up with is doing two separate mashes and combining the wort but I'm unsure if this will cause any flavor differences. I guess I could package the grains as two 5.5 gallon batches with the same ratios base/specialty grains in each batch and just do two separate mashes but I was hoping to shorten the brew day a bit more.
The recipe calls for a combined total of 41 lbs of grain. According to Bobby M's table - I max out at 37ish with a 15 gallon mash tun. I would be nervous even getting even close to that amount of grains in a 15 gallon pot.
What is the best way to deal with this? I'm hoping someone has a trick to do this without having to essentially mash twice. The only thing I have come up with is doing two separate mashes and combining the wort but I'm unsure if this will cause any flavor differences. I guess I could package the grains as two 5.5 gallon batches with the same ratios base/specialty grains in each batch and just do two separate mashes but I was hoping to shorten the brew day a bit more.