woodsconsin81
Member
- Joined
- Oct 23, 2008
- Messages
- 9
- Reaction score
- 0
I am about begin a partial mash recipe that I created. Of course I will be going through the mash and batch sparge processes, but I wanted to get people's feedback on water ratios because I really do not want to have to top-up my wort after I've completed the boil, chilled the wort and am putting the wort into the primary for pitching.
My question is this. I would like to end up with the typical five gallons of wort from a six gallon boil. Now as I go through the process, I'm aware of the following ratios for each stage:
1. 1.25 liters of water per lbs. of grain for the mash (then runoff)
2. 1.25 liters of water per lbs. of grain for the sparge (then runoff)
Now, this is a partial mash, so assuming that I have 5.25 lbs. of grain for the mash and sparge, this would leave me with 6.6 liters of water for each of the mash and sparge water, which would leave me with approximately 3.5 gallons of wort prior to the boil. Assuming water loss in grain absorbtion and boil off, this does not get me anywhere close to six gallons for a boil.
Now, if I factor in the dry malt extract, it would bring my grain bill to about 9.12 lbs., if I used the same ratio above I would come out with about 11.4 liters for both the mash and sparge water, or about 6 gallons of wort, so this makes more sense. However, is this still enough to get me through the boil and leave enough wort to fill a bit more than five gallons in my primary? My concern is that through absorption, boil off and loss from trub I will be left with less than my ideal amount of final wort.
Also, if I cannot factor in dry malt extract, where do I add that extra water? Do I add it prior to the boil, after I've completed both the mash and the sparge, or do I just have to live with topping up my primary (which I find leaves the final product a little watery, and probably no where close to where I wanted it).
Let me know what others have experienced/suggest. Thank you!
My question is this. I would like to end up with the typical five gallons of wort from a six gallon boil. Now as I go through the process, I'm aware of the following ratios for each stage:
1. 1.25 liters of water per lbs. of grain for the mash (then runoff)
2. 1.25 liters of water per lbs. of grain for the sparge (then runoff)
Now, this is a partial mash, so assuming that I have 5.25 lbs. of grain for the mash and sparge, this would leave me with 6.6 liters of water for each of the mash and sparge water, which would leave me with approximately 3.5 gallons of wort prior to the boil. Assuming water loss in grain absorbtion and boil off, this does not get me anywhere close to six gallons for a boil.
Now, if I factor in the dry malt extract, it would bring my grain bill to about 9.12 lbs., if I used the same ratio above I would come out with about 11.4 liters for both the mash and sparge water, or about 6 gallons of wort, so this makes more sense. However, is this still enough to get me through the boil and leave enough wort to fill a bit more than five gallons in my primary? My concern is that through absorption, boil off and loss from trub I will be left with less than my ideal amount of final wort.
Also, if I cannot factor in dry malt extract, where do I add that extra water? Do I add it prior to the boil, after I've completed both the mash and the sparge, or do I just have to live with topping up my primary (which I find leaves the final product a little watery, and probably no where close to where I wanted it).
Let me know what others have experienced/suggest. Thank you!