Does someone have an efficiency formula?

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impatient

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I plugged this into BeerTools

6 gallon boil
5 gallon batch
10lbs Munich Malt
3lbs Midwest Wheat Malt
3oz Cascade 60 minutes

They estimated 1.063 OG at 72%. I got 1.080 at 67 degrees or 1.081.

The way I figured my efficiency last time was by changing the percentage until there estimated OG matched what I got.

Does someone have a formula to make this easier.

IMG_0998.JPG
 
13# x 35 / 5g = 91

81/91=89%eff

pounds of grain x 35pointpergallon / batch size = maximun extraction

actual extraction/maximun extraction = extraction efficiency
 
I've always calculated my efficiency per-boil. Is there a reason to do it post boil? Would come out the same I suspect anyway.

The preboil efficiency tells you how efficient your mash/lauter process is and is helpfull when tweaking your crush and lautering process. A postboil efficiency (if calculated based on the OG and volume in your fermentor) gives you your "brewhouse" efficiency and will be less then your preboil efficency due to losses of volume to trub, absorbed by hops, trapped in vessels or tubes etc.

GT
 
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