Hi there folks,
My friends and I are feeling pretty adventurous and want to try brewing a parti-gyle recipe (this will be our third all-grain recipe, tenth recipe overall).
"Brewing Better Beer" by Gordon Strong gives away a recipe for an English Barley Wine/Brown Ale combo. Simplifying, it goes like this:
1- Mash 31lbs of Maris Otter for 90 minutes at 150F
2- Mash-out at 170F
3- No sparge, collect 8 gallons at 1.082 (then boil 120 minutes, adding hops)
4- Add 1.5 lbs crystal 80 and 1/4 lbs chocolate in the mash tun
5- Fill the mash tun with 170F water and steep for 30 minutes
6- Collect 7.5 gallons at 1.040 (then boil 75 minutes)
My main question is: how much water in each step ?
Let me do the math, and you tell me if it is correct.
The grain absorbs 0.13 gal/lb, and we may include (as BrewPal does, but I fail to understand how to do a no sparge with this software) a "system loss" of .25 gal. So if I want to retrieve 8 gallons in step 3, I should strike with 12.28 gal, then mash-out using decoction. The Maris Otter is now saturated in water, so step 5 should only account for the water absorption of the Crystal and Chocolate, so if I want to retrieve 7.5 gal in step 6, I should add 7.7 gal.
Overall, this gives a water-to-grist ration of 1.58 for the main recipe, which seems about right.
Is everything right? Any comment or technique I should know while brewing parti-gyle? Thanks
EDIT: Added question in #9: My MLT is probably too small for 31# of grains + 12gal of water. Is it alright to divide this in two mashes (i.e., two parti-gyles with half the ingredients each time)?
My friends and I are feeling pretty adventurous and want to try brewing a parti-gyle recipe (this will be our third all-grain recipe, tenth recipe overall).
"Brewing Better Beer" by Gordon Strong gives away a recipe for an English Barley Wine/Brown Ale combo. Simplifying, it goes like this:
1- Mash 31lbs of Maris Otter for 90 minutes at 150F
2- Mash-out at 170F
3- No sparge, collect 8 gallons at 1.082 (then boil 120 minutes, adding hops)
4- Add 1.5 lbs crystal 80 and 1/4 lbs chocolate in the mash tun
5- Fill the mash tun with 170F water and steep for 30 minutes
6- Collect 7.5 gallons at 1.040 (then boil 75 minutes)
My main question is: how much water in each step ?
Let me do the math, and you tell me if it is correct.
The grain absorbs 0.13 gal/lb, and we may include (as BrewPal does, but I fail to understand how to do a no sparge with this software) a "system loss" of .25 gal. So if I want to retrieve 8 gallons in step 3, I should strike with 12.28 gal, then mash-out using decoction. The Maris Otter is now saturated in water, so step 5 should only account for the water absorption of the Crystal and Chocolate, so if I want to retrieve 7.5 gal in step 6, I should add 7.7 gal.
Overall, this gives a water-to-grist ration of 1.58 for the main recipe, which seems about right.
Is everything right? Any comment or technique I should know while brewing parti-gyle? Thanks
EDIT: Added question in #9: My MLT is probably too small for 31# of grains + 12gal of water. Is it alright to divide this in two mashes (i.e., two parti-gyles with half the ingredients each time)?