calculation problem - help

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400d

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ok I know this is not about beer, but still couldn't find better place to post it. I have a mead that is fermenting for more than a month. It's 5 liters (1.32 gallons)

Original gravity was 1.135 and after a month I added 0.5 liters (0.132 gallons) of water to top up because the head space could cause oxidation after a long time.

now, how do I know what is the exact OG and how do I calculate % alcohol after this dilution?

thanks!
 
what is 1.452 in this calculation?

it's a simple relationship

original gravity / original volume = new gravity / new volume.

OG = 1.135 (use 135)
OV = 1.32 gal
NV = 1.32 + .132 as you stated, so 1.452
solve for NG
 
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