ohiodad
Well-Known Member
What is the calculation to caculate this?
Actual Attenuation
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Iordz
Well-Known Member
(OG-FG)/(OG)=%A
I have a beer that started at 1.040, ended at 1.010, that is the attenuation?
(40-10)/(40)=75%A
I have a beer that started at 1.040, ended at 1.010, that is the attenuation?
(40-10)/(40)=75%A
Got Trub?
Well-Known Member
Iordz said:
To clarify:
(OG-FG)/(OG) * 100 = %A
OP
OP
ohiodad
Well-Known Member
Got Trub? said:
Thanks a bunch.. I thought that was it.. Doesn't work out the same though if you put the 1. in front of the og and fg.. Doh! Thanks again!
isn't that apparent attenuation?
Iordz
Well-Known Member
Sorry, I was too vague. You multiply by 100, I just thought it was pretty much a given. I believe this is actual attenuation, it makes sense, you are calculating how much the beer, actually, attenuated.
Got Trub?
Well-Known Member
DB is correct - the formula is for apparent attenuation. That is what we measure with our hydrometer. As alcohol is less dense then water and our fermenting/ed beer has alcohol in it it will throw off your hydrometer reading. While of theoretical importance actual attenuation has little practical use in homebrewing as all attenuation numbers we use are of the apparent variety.
