Ranger9913

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I seem to remember that being said in another post somewhere. I have a DPDT switch wired (Manual-OFF-Auto). The manual side receives it power right from the dist-block, and the Auto receives a power feed from the SSR. However, if the switch is in Auto mode but I don't have the relay turned on my voltmeter is still showing about 3VAC. I wired a small LED off the middle terminals of the switch so that when power goes to the outlet the light turns on. This works perfectly in Manual mode but the light also comes on during Auto mode even though the SSR is not switched on.

weirdboy

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I think you mean leak current. There is no such thing as leaking voltage.

I don't know about your particular SSR, but transistors and related devices pretty much always leak some current when power is applied to them. It's not a mechanical system like an actuated relay.

illin8

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Yes, I believe they do until a certain load is applied to them. Search you should be able to find it easily.

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Synovia

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There is no on and off, there is only Hi/Low.

Ranger9913

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Okay, so in other words the reason my LED light turns on is because the SSR is supplying a current at all times regardless if the SSR is open or closed?

Anyone know of way to wire an LED to only light up when the SSR is activated/closed?

samc

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There was a discussion on the BCS forum about this subject. Do a search, don't remember the outcome.

Poobah58

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An SSR is a triac circuit. You cannot put an LED across it (unless you install a load resistor). You should use an incandescent light. The triac can leak just enough current to light an LED (comes on at a lower voltage than a light bulb) but doesn't have enough current to drive a light bulb.

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Ranger9913

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ah ok, makes sense now.

MrH

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I use line voltage LEDs and run them off the high side. Works like a charm.


MrH

Ranger9913

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What exactly is the "high side"?