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Old 02-21-2009, 03:50 AM   #1
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Default 500 watt or other low watt elements

Does anyone know where to get very low wattage heater elements?



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Old 02-21-2009, 04:04 AM   #2
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im not sure you can find a low watt element. what most people do is install a 110 volt high watt element onto a 220 volt circuit and run a pulse width generator to it to vary the output from the 220 to about 60-65 percent allowing for a low wattage step-in without destroying your 110 volt element.



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Old 02-21-2009, 05:18 AM   #3
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Quote:
Does anyone know where to get very low wattage heater elements?
Chromalox is one of many suppliers


Just some info:
If you connect any 240 V heater element to a 120 V circuit your effective wattage is 1/4.

2000 W, 240 V element = 500 W if connected to 120 V

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Old 02-21-2009, 12:29 PM   #4
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I might have one laying around that will get you 500w. How short does it have to be?

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Old 02-21-2009, 12:34 PM   #5
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What do you want to use it for?

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Old 02-21-2009, 03:34 PM   #6
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I have a super secret shark-laser project underway! So I can't tell yet... in case it's a complete disaster - which might end up being the case. I have an unreputation I need to keep intact. I definately will look into the 240 volt element.... good idea. However I though t it would be 1/2 not 1/4 of the power.

The element needs to be very very low-density...like maybe 25 watts per square inch.

OK - I will tell you...

http://www.arttec.net/Solar/10-9/Oct9.html

But instead I am using an old dc to ac power inverter I have laying around to drive the solar rims system.

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Old 02-21-2009, 09:08 PM   #7
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Quote:
However I though t it would be 1/2 not 1/4 of the power.
No, P=E²/R or P= I*E, E= Element voltage, R= Element resistance
We don't know the resistance of the element or the current.
The formula for the resistance is: R= E/I
The formula for the current is: I=P/E
Let's calculate the current:

P=2000W, E= 240 V
I= P/E, 2000/240= 8.333 Amps

Let's calculate the resistance:
R= 240/8.333= 28.80 Ohms (Element resitance)

Now if we use the 2000 W, 240 V element with 120 V we get :
P= E²/R, 120²= 14400/28.80= 500 W



Cheers,
ClaudiusB


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