Quote:
Originally Posted by shay1989
I have a question that Im sure there is an easy answer for that I just don't know so if someone wouldn't mind steering me the right direction on this recipe I am attempting I would really appreciate it. I'm going to make an Arrogant Bastard clone and I want to end up with about (7 gal) of wart because it's a 90 minute boil and I want (5 gal) when its done boiling. I'm going to be batch sparging which I think is about 75% efficiency according to my book. (this is my first attempt at an all-grain if you couldn't tell.) So first off if it calls for 16 pounds of grain and a desired OG of 1.071, is there a way to calculate how much water I need to sparge with to come out with 7 gallons of wart(since I'm assuming the grains will soak up quite a bit) and if I'm batch sparging do I need to increase my amount of grains? I grind them at my LHBS. Even after reading through a lot of the threads I'm still pretty confused on this
|
16lb total grain
16x1.5 (qts of water calculation)= 24 qtrs of water divided by 4(4 qts in a gallon) = 6 gal water for the mash
16x.125 (grain absorption calculation) = 2 gal of water absorbed by grains during mash
6-2= 4 gals of wort is what you should get from the mash
So 7 (total boil amount needed) -4 (wort amount already collected) = 3 gal of water needed to sparge with
Hopefully that helps you. You will should get about 4 gallons of wort from the mash then will need 3 more gallons to sparge with to reach your 7 gallon boil size. It might be a little more then 3 gallons depending on ur MLT setup and what not but this should get you started.