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 Home Brew Forums > mash efficiency

05-07-2012, 11:37 AM   #1
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 mash efficiency

Does anyone have an easy equation to figure mash efficiency? I brewed my second batch of all grain yesterday. I didn't figure eff. For my first batch, but I wanted to for this batch. I was reading Palmer's how to brew, I might of had one to many by the time I was reading it: ) but I couldn't figure it out.

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05-07-2012, 03:27 PM   #2
TyTanium
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It's really easy.

Gravity Points x Volume = Gravity Units

So say you had 5 gallons of 1.050. 50 x 5 = 250 gravity units

Divide your actual number into the 100% efficiency number. Let's say it's 312.
250/312 = 80% efficiency.

As for the 312...that's determined by your recipe. A good approximation is (Grain weight) x 37. Each grain has a theoretical 100% effieciency extraction, often listed as Points per Pound per Gallon, or PPG. Most base malt is ~37 (meaning 1 pound in 1 gallon gives you 1.037).

Important note: There are a variety of efficiency measures:

• Mash efficiency: How much starch is converted to soluable sugar
• Lauter efficiency: How much of the sugar is extracted versus left stuck in the grain bed
• Brewhouse efficiency: How much of the sugar made it into your fermenter

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05-07-2012, 08:41 PM   #3
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Thanks. That makes sense. Its all starting to come together now.

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05-07-2012, 08:53 PM   #4
Hammy71
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Or if your lazy like me, and don't have Beersmith yet....