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Old 10-16-2008, 04:27 AM   #1
oswegan
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Default Help Calculating boil gravity

Is boil gravity calculated using the target volume of a recipe (e.g. 10 gallons) or the preboil volume (13 gallons)?

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Old 10-16-2008, 04:51 AM   #2
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I am assuming that by "boil gravity" you mean the gravity of the wort before the boil. The way I would solve for that if I knew I wanted 10 gallons of boiled wort that was 1.060 would be to multiply 10 times 60 which equals 600. If you are going to start with 13 gallons, (and boil away three) the gravity at the beginning of the boil would be 600 divided by 13, which is about 46, or 1.046.

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Old 10-16-2008, 01:55 PM   #3
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Sorry, I should have been more specific.

I am trying to calculate IBUs after the fact. I had a preboil gravity of 1.051 in 13 gallons, and a post boil original gravity of 1.061 in 10 gallons.

For purposes of the IBU calculation which one do I use?

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Old 10-16-2008, 01:59 PM   #4
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Pre-boil. Though it's more complicated than that. Because you're evaporating and concentrating the wort, the utilization changes over the course of the boil. You may start at 30% and drop to 25%; which skews your IBU calculations.

Speaking of which, do you know your kettle utilization?

Bob

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Old 10-16-2008, 02:27 PM   #5
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I don't. It was the first time I had used the kettle.

I started with about 13 gallons and added 10oz of loose hops over the course of a 60 minute boil and ended up with just over 10 gallons. The hops probably soaked up quite a bit.

How do I figure kettle utilization, and for the gravity and boil volume, should I split the difference?

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