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Old 10-28-2008, 12:57 AM   #1
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Default First All Grain session was a success!

I know there are a lot of "First All Grain" posts, however I have some specific questions after this run.

I'm not going to obsess over my efficiencies in general, however for my first few all grain batches, I'm going to track them til we get mid-80's or low 90's.

My biggest question is more regarding something dumb that I did than technique (maybe thats the same thing).

I took my First runnings gravity, batch sparge 1 gravity and batch sparge 2 gravity, however somehow I forgot to get a sample once we starting heating for the full boil. How can I get a decent estimate on what my SG would have been?

Also, what would a decent estimate be for grain absorbtion? x quarts of water absorbed by x pounds of grain?

Thanks for all the advice while we moved to all grain. Many of you have been a real help.

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Old 10-28-2008, 02:06 AM   #2
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Congratulations, welcome to the obsession.

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Old 10-28-2008, 02:17 AM   #3
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IIRC, .12 gallons per pound of grain is a typical absorption. If you were sure of your volumes for each of the runnings, you can do a straight average.

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Old 10-28-2008, 02:20 AM   #4
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Thanks Bobby,

From what I would assume on that .12 gallons water/lb grain, that would be during the initial mash, since during the sparge the grains should have already absorbed water to their potential. Since we aren't "squeezing" out the grains, they should not absorb much water during the sparge. Would that be correct?

I tried the math, however it doesn't make much sense to me, since we ended up with 1.056 OG into the fermenter, and boiled off almost 2 gallons. That should make the wort's OG reading more concentrated than the SG.

13.75 qts of water for mash, running off ~ 2.2 gallons @ 1.085
11.3 qts for first sparge, running off ~ 11 qts @ 1.055
11.3 qts for second sparge, running off ~ 11 qts @ 1.018

We started at a little over 7 gallons, and expected to boil off about 1.5 gallons (we boiled off almost 2)

My math would be [(2.2 X 85) + (2.75 X 55) + (2.75 X 18)]/7 gallons = 1.055

Shouldnt this boil off to a higher concentration than what I got for my OG of 1.056?

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Old 10-28-2008, 02:22 AM   #5
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I figure my absorbtion to be .15 gallons per pound. You only need to account for it in the mash.

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Old 10-28-2008, 02:30 AM   #6
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Right, the grain is saturated already so any sparge you put in comes out.

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Old 10-28-2008, 03:05 AM   #7
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I use this spreadsheet to calculate strike and sparge volumes, and I'm generally right on target.

http://www.bayareamashers.org/conten...atchSparge.xls

Plus it has the formulas and whatnot so you can see what the numbers are behind the calcs if you'd like.

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Old 10-28-2008, 04:12 AM   #8
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Quote:
Originally Posted by NoClueBrewMaster View Post
Thanks Bobby,

From what I would assume on that .12 gallons water/lb grain, that would be during the initial mash, since during the sparge the grains should have already absorbed water to their potential. Since we aren't "squeezing" out the grains, they should not absorb much water during the sparge. Would that be correct?

I tried the math, however it doesn't make much sense to me, since we ended up with 1.056 OG into the fermenter, and boiled off almost 2 gallons. That should make the wort's OG reading more concentrated than the SG.

13.75 qts of water for mash, running off ~ 2.2 gallons @ 1.085
11.3 qts for first sparge, running off ~ 11 qts @ 1.055
11.3 qts for second sparge, running off ~ 11 qts @ 1.018

We started at a little over 7 gallons, and expected to boil off about 1.5 gallons (we boiled off almost 2)

My math would be [(2.2 X 85) + (2.75 X 55) + (2.75 X 18)]/7 gallons = 1.055

Shouldnt this boil off to a higher concentration than what I got for my OG of 1.056?
[(2.2*85)+(2.75*55)+(2.75*18)]/7.7G=1.050
check your own math plz
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Old 10-28-2008, 04:49 AM   #9
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I got 1.055 too, sorry erik

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Old 10-28-2008, 04:57 AM   #10
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Quote:
Originally Posted by eriktlupus View Post
[(2.2*85)+(2.75*55)+(2.75*18)]/7.7G=1.050
check your own math plz
Quote:
Originally Posted by patrck17 View Post
I got 1.055 too, sorry erik
you get 1.055 only when you use 7g as your diviser but if you add up his collection amount it totals 7.7g
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grains in pounds(G) X 36(average points per gallon of grains) / batch size in gallons(g) = maximum efficiency(ME)
OG / ME = brewhouse efficiency

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