ok I know this is not about beer, but still couldn't find better place to post it. I have a mead that is fermenting for more than a month. It's 5 liters (1.32 gallons)
Original gravity was 1.135 and after a month I added 0.5 liters (0.132 gallons) of water to top up because the head space could cause oxidation after a long time.
now, how do I know what is the exact OG and how do I calculate % alcohol after this dilution?
1.32*135 = 178.2
178.2 / 1.452 = 122.7
og = 1.123 (Rounded up)
Your total volume. (1.32 gallons) + (0.132 gallons)