I'm guessing at this and with the help of a different post:
http://www.homebrewtalk.com/f25/calculating-gravity-101641/
I was helped with a similar question earlier today, here's my thought:
4gal(1.070sg) + 1gal('x'sg) = 5gal(1.090)
4(1.070) + 1x = 5(1.090)
4.28 + x = 5.45
x = 1.17, you want your additional gallon with SG of 1.170
If 1# sugar added to 1 gallon of water sets the SG to 1.046, it has raised the SG by .046 and you want to raise it by .17; divide .17 by .046 for # of sugar. 0.17/.046 = 3.7# sugar to 1 gallon water for SG 1.170.
Hopefully somebody who knows will chime in, but I think that should work.
I hope I didn't turn something simple into something difficult... Best Wishes!