No. Elements are fixed resistance, so if you drop the voltage the current will drop as well.
Use I = V/R to find the current at any voltage (I = Amps, V = the RMS voltage, or say 110).
For your element, the fixed resistance of the element, R, is 7.2 ohms. (R = V^2/W = 120^2 / 2000 = 7.2)
So, @ 110V, the current is I = V/R = 110/7.2 = 15.3A