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Old 12-10-2012, 02:06 AM   #1
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Default Mixed Drink ABV Calculation

Ok, maybe I'm making this more complicated than I have to but could I get a little help figuring this out? This year we've made "Apple Pie Liquor".. we bottle it in mason jars and give it as gifts for Christmas. Tastes sooo good! I want to make labels this year with the ABV on it..

the recipe consists of..

1.5 gal Apple Juice @ 0% ABV
1 gal Apple Cider @ 0% ABV
6 cups Everclear @ 95% ABV
1 cup Buttershots @ 15% ABV
1 cup Gold Schlager @ 43.5% ABV

So what would my total ABV be? My calculations put me at about 13% but that sounds too low.

If anyone's interested in the rest of the recipe (yields about 12 qts)..

Bring Apple Juice + Cider + Spices to boil, simmer 20 minutes
(Spices: 2 tsp apple pie spice, 10 cinnamon sticks, 2 cup brown sugar)
Cool to room temp, add alcohol + 2 tbs vanilla, mix thoroughly, transfer to jars.

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Old 12-10-2012, 02:10 AM   #2
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Originally Posted by nullvalue View Post
Ok, maybe I'm making this more complicated than I have to but could I get a little help figuring this out? This year we've made "Apple Pie Liquor".. we bottle it in mason jars and give it as gifts for Christmas. Tastes sooo good! I want to make labels this year with the ABV on it..

the recipe consists of..

1.5 gal Apple Juice @ 0% ABV
1 gal Apple Cider @ 0% ABV
6 cups Everclear @ 95% ABV
1 cup Buttershots @ 15% ABV
1 cup Gold Schlager @ 43.5% ABV

So what would my total ABV be? My calculations put me at about 13% but that sounds too low.

If anyone's interested in the rest of the recipe (yields about 12 qts)..

Bring Apple Juice + Cider + Spices to boil, simmer 20 minutes
(Spices: 2 tsp apple pie spice, 10 cinnamon sticks, 2 cup brown sugar)
Cool to room temp, add alcohol + 2 tbs vanilla, mix thoroughly, transfer to jars.
That's what I come up with, too.
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Old 12-10-2012, 02:21 AM   #3
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Same here.

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Old 12-10-2012, 02:40 AM   #4
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Awesome, I guess I can do math! If you tasted this stuff you'd swear it was higher! thanks guys

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Old 12-10-2012, 04:13 AM   #5
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Originally Posted by nullvalue View Post
Ok, maybe I'm making this more complicated than I have to but could I get a little help figuring this out? This year we've made "Apple Pie Liquor".. we bottle it in mason jars and give it as gifts for Christmas. Tastes sooo good! I want to make labels this year with the ABV on it..

the recipe consists of..

1.5 gal Apple Juice @ 0% ABV
1 gal Apple Cider @ 0% ABV
6 cups Everclear @ 95% ABV
1 cup Buttershots @ 15% ABV
1 cup Gold Schlager @ 43.5% ABV

So what would my total ABV be? My calculations put me at about 13% but that sounds too low.

If anyone's interested in the rest of the recipe (yields about 12 qts)..

Bring Apple Juice + Cider + Spices to boil, simmer 20 minutes
(Spices: 2 tsp apple pie spice, 10 cinnamon sticks, 2 cup brown sugar)
Cool to room temp, add alcohol + 2 tbs vanilla, mix thoroughly, transfer to jars.

Total volume = 384 oz

Total alcohol = 25.14 oz

25.14/384 = .0654687

.0654687 X 2 = 13.0974 Proof
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Old 12-10-2012, 04:20 AM   #6
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Total volume = 384 oz

Total alcohol = 25.14 oz

25.14/384 = .0654687

.0654687 X 2 = 13.0974 Proof
Nah, it's ~50oz of ethanol. 13% ABV, 26 proof.
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Old 12-10-2012, 01:58 PM   #7
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You need to take into account the fact that if you add 20 mL of ethanol (15.785 grams @20 °C) to 80 mL of water (79.852 grams @ 20 °C) you get an 20% ABV solution with volume 98.238 cc i.e. not 100 cc. The alcohol molecules slip in between the water molecules to some extent so the volumes don't add.

6 cups of Everclear gives 6*236.6*.95*0.789239 = 1064.38 grams EtOH

1 cup of Buttershots gives 1*236.6*0.15*0.789239 = 28.0101 grams

1 cup of Gold Schlager gives 1*236.6*0.435*0.789239 = 81.2293 grams

for a total alcohol content of 1173.62 grams EtOH.

Now you need the total weight of the mixture. For the sake of getting some numbers we'll make some guesses. You should either weigh all the components (before or after mixing) or measure the specific gravity and volume and get the weight from SG*0.998203*Volume. You'll need specific gravity in any event. In the calculations below all the extra decimal places are there because I am pasting from a calculation utility program. They are not justified:

1.5 gal cider at 6 °P weighs 1.5*3.785*1.02369*0.998203 = 5.80156 kg
1 gal juice at 6 °P weighs 1*3.785*1.02369*0.998203 = 3.8677 kg
6 cups Everclear weighs 6*0.2366*0.81138 = 1.15184 kg
1 cup Buttershots weighs 1*0.2366*(1?)= 0.2366 kg
1 cup Gold Schlager weighs 1*0.2366(0.96?) = 0.2272 kg

for a total of 11.285 kg. Thus the ABW is 100*1.17362/11.2848 = 10.4%. To find ABW we need the specific gravity of the mixture. 10.4% ABW means 100 grams of solution has 10.4 grams of ethanol in it. The volume of 10.4 grams of ethanol is 10.4/(SG_EtOH*0.998203) and the volume of 100 grams of solution is 100/(SG_solution*0.998203) thus the ABV is ABW*(SG_solution/SG_EtOH). The specific gravity (20/20) of EtOH is 0.79066 so

ABV = ABW*(SG_solution/0.79066)

Assuming the SG of the mix to be essentially that of 6°P apple juice (and that's a WAG, of course) which is 1.02369 you would have

ABV = ABW*(1.02369/0.79066) = 10.4*(1.02369/0.79066) = 13.4652

or 27 proof. Now the first thing you should note after all this is that the numbers don't differ appreciably from what you calculated by ignoring the volume effect so that even if your measured SG and volume differ from the estimates I made the result won't be that much different. Obviously if one were to do this frequently he'd want to put the calculations in a spreadsheet.

One other note: all the EtOH density numbers I used were taken from the OIML polynomial for 20 °C. The TTB uses AOAC density data which is at 60 °F.

Edit: Just noted that the apple cider/juice are simmered. This will result in water loss and thus higher final ABV. Be sure to measure volume and SG after this simmering.

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Old 12-11-2012, 05:32 PM   #8
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Originally Posted by ajdelange View Post
You need to take into account the fact that if you add 20 mL of ethanol (15.785 grams @20 °C) to 80 mL of water (79.852 grams @ 20 °C) you get an 20% ABV solution with volume 98.238 cc i.e. not 100 cc. The alcohol molecules slip in between the water molecules to some extent so the volumes don't add.

6 cups of Everclear gives 6*236.6*.95*0.789239 = 1064.38 grams EtOH

1 cup of Buttershots gives 1*236.6*0.15*0.789239 = 28.0101 grams

1 cup of Gold Schlager gives 1*236.6*0.435*0.789239 = 81.2293 grams

for a total alcohol content of 1173.62 grams EtOH.

Now you need the total weight of the mixture. For the sake of getting some numbers we'll make some guesses. You should either weigh all the components (before or after mixing) or measure the specific gravity and volume and get the weight from SG*0.998203*Volume. You'll need specific gravity in any event. In the calculations below all the extra decimal places are there because I am pasting from a calculation utility program. They are not justified:

1.5 gal cider at 6 °P weighs 1.5*3.785*1.02369*0.998203 = 5.80156 kg
1 gal juice at 6 °P weighs 1*3.785*1.02369*0.998203 = 3.8677 kg
6 cups Everclear weighs 6*0.2366*0.81138 = 1.15184 kg
1 cup Buttershots weighs 1*0.2366*(1?)= 0.2366 kg
1 cup Gold Schlager weighs 1*0.2366(0.96?) = 0.2272 kg

for a total of 11.285 kg. Thus the ABW is 100*1.17362/11.2848 = 10.4%. To find ABW we need the specific gravity of the mixture. 10.4% ABW means 100 grams of solution has 10.4 grams of ethanol in it. The volume of 10.4 grams of ethanol is 10.4/(SG_EtOH*0.998203) and the volume of 100 grams of solution is 100/(SG_solution*0.998203) thus the ABV is ABW*(SG_solution/SG_EtOH). The specific gravity (20/20) of EtOH is 0.79066 so

ABV = ABW*(SG_solution/0.79066)

Assuming the SG of the mix to be essentially that of 6°P apple juice (and that's a WAG, of course) which is 1.02369 you would have

ABV = ABW*(1.02369/0.79066) = 10.4*(1.02369/0.79066) = 13.4652

or 27 proof. Now the first thing you should note after all this is that the numbers don't differ appreciably from what you calculated by ignoring the volume effect so that even if your measured SG and volume differ from the estimates I made the result won't be that much different. Obviously if one were to do this frequently he'd want to put the calculations in a spreadsheet.

One other note: all the EtOH density numbers I used were taken from the OIML polynomial for 20 °C. The TTB uses AOAC density data which is at 60 °F.

Edit: Just noted that the apple cider/juice are simmered. This will result in water loss and thus higher final ABV. Be sure to measure volume and SG after this simmering.
Wow! I knew someone would come up with an answer like this! Next year I'll calculate it like this. Thank you
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Old 12-11-2012, 05:43 PM   #9
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i would also ensure your everclear is indeed the 190 proof stuff - here in Wisconsin we can only get the 151 proof

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