Quote:
Originally Posted by SpanishCastleAle
So pH is a measurement of H+ ions. Suppose we have a substance accepts or donates OH- ions (implying it does not directly affect the H+ ions)...how does that change the pH? Since pH is a measure of the H+ and not the OH-.
Is it because:
In the case of an OH- acceptor, water molecules disassociate and form more OH- and H+ ions...yielding a resultant increase in H+.
In the case of an OH- donator, the extra OH- joins with some of the existing H+ to form water...yielding a resultant decrease in H+.
???
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In the Bronstead-Lowry theory of acids and bases, an acid is a proton donator, and a base is a proton accepter. Under this model, strong bases such as NaOH (Sodium Hydroxide or Lye) dissociate into Sodium ions and OH groups. Weaker bases act similarly, but dissociate less fully. Acids do the same thing, but form H+ and some negatively-charged ion. Here "weak" and "strong" are not measures of pH, but measures of how readily the acid or base dissociates.
The "OH acceptor" that you're asking about is a proton. When a H+ and OH- combine, they form water. Pure water has both OH- and H+ present in very small quantities (in any aqueous solution, the concentration of OH times the concentration of H+ = 1x10^-14 As you might expect, the concentrations of each in pure water are equal at 1x10^-7, which leads to the definition of pH=7 as that of pure water).
When something that "donates" OH- ions (which is equivalent to accepting H+ ions) is added to a system in equilibrium, the equilibrium will shift one way or the other due to the H+ + OH- = H2O reaction. This shift is easy to calculate for strong acids and bases, and less easy for weak acids/bases. This goes into the math that Kaiser is purposefully avoiding (people tend to be intimidated by logarithms).