Of the three value reported "as CaCO3" none actually is the amount of calcium carbonate dissolved but rather a measure of the equivalence of, respectively, the amount of acid required to lower sample pH to 4.3 (alkalinity - this is the one you are interested in), the equivalence of the amount of EDTA required to chelate all the calcium and magnesium (total hardness) and the total hardness minus the equivalence of calicum and magnesium, all muliplied by 50 (because if 100 mg of calcium carbonate is dissolved in a liter of water using natures way, i.e. carbon dioxide) there will be, at normal potable water pH, 2 mEq/L calcium and approximately 2 mEq/L bicarbonate. 2 mEq/L * 50 = 100 ppm "as CaCO3". So total alkalinity of 44 corresponds to 44/50 = .88 mEq/L. As nearly all the acid in the alkalinity titration would go into H+ + HCO3- --> H2O + CO2 the equivalence of bicarbonate is the same and, as the equivalent weight of bicarbonate is 61 the bicarbonate concentration is 0.88*61.
If the chlorine is indeed all free (as opposed to the amount in chloramine expressed as free chlorine) then you should have no problem with it but it is simple enough to test whether it is likely to be problematical. In a nutshell, if you can't smell it it won't bother you. Let some of the water stand in a beaker overnight. If it doesn't smell of chlorine in the morning then there was no chloramine and you can proceed. If it does, there is chloramine in which case just add a quarter of a Campden tablet for each 5 gallons and brew with that.