Calculating strike water temp  HELP
I saw other threads but I am having a tough time figuring this out.
Initial Infusion Equation: Strike Water Temperature Tw = (.2/r)(T2  T1) + T2 where: r = The ratio of water to grain in quarts per pound. 11.875 lbs of grain (divided by) 3.7 gal (1.25 gt per lb) = .31 T1 = The initial temperature (¡F) of the mash. 60' T2 = The target temperature (¡F) of the mash. 165' Tw = The actual temperature (¡F) of the infusion water. So: (.2 / .31 = .64)(165 60 = 105) + 165 So: .64 x 105 +165 So: 67.5 +165 = 200+... That can't be right... What am I doing wrong??? 
in your equation r should be 1.25 not .31

Thanks for the note on that one. That still leaves my strike water temp at 182'. Isn't that a little high? or is that accounting for heat loss due to the added grain?

I agree that r should be between 1 and 2, and 1.25 is a good starting point
But surely you're not going to mash at 165. 154 seems to be a reasonable value So: (.2 / 1.25 = .16)(154  60 = 94) + 154 So:.16 * 94 + 154 = 169 That looks pretty reasonable to me. a. 
http://www.garagebrewers.com/forum/topic?f=14&t=1072 is the recipe I have planned to follow... Guy says its legit. I know not to believe everything I read... but
thanks for the notes. 
I see a mash temp of 156 vs 165. Which is a perfectly reasonable temp for a full bodied beer.

hi dyslexia how are you! sorry everyone, AJF as exactly right...

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