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Old 09-09-2011, 01:33 AM   #11
michaeltrego
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will do! I'm mashing right now. I'm sure things will work out differently than predicted, but I'll go back and calculate with the volumes and SG that I end up with, to see how things work out.
I'm curious about your parti-gyle session - how did it go?
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Old 09-09-2011, 02:39 AM   #12
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I'm curious about your parti-gyle session - how did it go?
poorly, in fact it's still going. It's been three days!
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making (C6H10O5)n- into C12H22O11 and then into C2H5OH, and then getting drunk

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Old 09-09-2011, 02:56 AM   #13
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Three days....I thought you were brewing yesterday?

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Old 09-09-2011, 05:24 AM   #14
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Three days....I thought you were brewing yesterday?
I started early. Anyway I'm boiling now. It will take some time to figure out my notes. I really botched the calculations on this SRM thing because of a sparging technique I tried. I mashed 7lb of base, and use the sparge from that as the mash and sparge water for the second mash. I should have used the other grain in that, but I'll see if I can figure out what ended up happening, and calculate from that. It's been a long few days. I need a shower and a clean shirt.
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making (C6H10O5)n- into C12H22O11 and then into C2H5OH, and then getting drunk

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Old 09-09-2011, 12:19 PM   #15
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SRM = 12.7*A430 = 12.7*e*c*1 where A430 is the absorption in a 1 cm cell at 430 nm, e is the extinction coefficient and c is the molar concentration. Making lots of somewhat shaky assumptions one can reason, therefore, that a 20 °P wort from a parti gyle mash would have twice the SRM of a 10 °P wort from the same mash (because °P, while they are not a molar concentration unit reasonably closely approximate one). Thus, if you believe in the commonly used MCU scheme for calculating color and you treat both gyles the same with respect to length of boil then you might be able to come up with rough estimates of the color by linear apportionment.

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