Originally Posted by MattHollingsworth
I couldn't find any equations or a calculator for this, so if anybody knows either, that'd be great.
I just added 160 ml of whiskey to a RIS (along with the wood that was soaking in it). This is 20.75 liters at 9.8% abv, for the stout, mixed with that 160 ml of whiskey that is 45% abv.
Naturally, I want to calculate the new alcohol content for the RIS. Help?
Well I would do it like this
20.75*.098=2.0335 L alcohol in beer
.16*.45=.072L alcohol in whisky
Then do ((total alcohol)/(total volume))*100